work

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through some ************* the
way i determined

ou could do this is 2 but its cleaner in 3) is to use a DIVISON

and then testing primality of
******* and q******* and if they both return prime, then outpt is a *on*, otherwise
increment
*
ivi and redo the process while divisor is less than input
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aHCn78*sna9732k.LQ

«

asdf

Too little time.

22 today.

While I'm overwhelmingly happy with the situation I've stumbled into, I can't help but feel time is just slipping away from me,

running over my body and
swirling down the drain.

the dirt washed off long ago.

I need to quit spending all my time in the shower and go to work.

Clock's ticking.